4x^2-(1-x^2)=(1/2)x^2

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Solution for 4x^2-(1-x^2)=(1/2)x^2 equation: 


x in (-oo:+oo)

4*x^2+x^2-1 = (1/2)*x^2 // - (1/2)*x^2

4*x^2+x^2-((1/2)*x^2)-1 = 0

4*x^2+x^2+(-1/2)*x^2-1 = 0

9/2*x^2 = 1 // : 9/2

x^2 = 2/9

x^2 = 2/9 // ^ 1/2

abs(x) = (2/9)^(1/2)

x = (2/9)^(1/2) or x = -(2/9)^(1/2)

x in { (2/9)^(1/2), -(2/9)^(1/2) }

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